In fig. 9.3 if ∠aob 125° then ∠cod is equal t
WebIn Fig. 9.3, if AOB = 125°, then COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution: ABCD is a quadrilateral circumscribing the circle We know that, the opposite sides of a … WebExample 10. Draw an angle equal to the difference of two angles given in Fig. 9.5. Solution: 1. Draw an angle ABC equal to ∠DEF (as ∠DEF > ∠PQR), using ruler and compasses. 2. With BC as one of the arms, draw an angle SBC equal to ∠PQR such that BS is in the interior of ∠ABC as shown in Fig. 9.6. Then, ∠ABS is the required
In fig. 9.3 if ∠aob 125° then ∠cod is equal t
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WebApr 27, 2024 · In figure, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution: (D) We know that the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. ⇒ ∠AOB + ∠COD = 180° ⇒ ∠COD = 180° – ∠AOB = 180° – 125° = 55° Question 3 WebJan 9, 2024 · In Fig., O is the centre of the circle. If ∠APB∠APB= 50°, find ∠AOB and ∠OAB. Solution: ∠APB=50° By degree measure theorem ∠AOB=2APB ∠APB=2*50°=100° since OA=OB [Radius of circle] Then ∠OAB=∠OBA [Angles opposite to equal sides] Let ∠OAB=x In OAb, by angle sum property ∠OAB+∠OBA+∠AOB=180° x+x+100°=180° 2x=180°-100° …
WebSep 13, 2024 · In fig., A, B, C and D are four points on a circle.AC and BD intersect at a point E such that ∠BEC=130° and ∠ECD=20°. Find ∠BAC. Solution: Given: ∠BEC=130°,∠ECD=20° To find: ∠BAC? Solution: In ∆EDC ∠E=180°-130° ——— [linear pair] ∠E=50° ∠E+∠C+∠D=180° —— [angle sum property of triangle] 50°+20°+∠D=180° 70°+∠D=180° ∠D=180/70=110° WebDec 14, 2024 · In the given figure, if ∠AOB=125∘, then ∠COD is equal to: (A) 62.5∘ (B) 45∘ (C) 35∘ (D) 55∘ ... After some time, the angle of elevation reduces to 3 0 ∘ (see Fig. 9.13). Find the distance travelled by the balloon during the interval. 15. …
WebIn Fig. 9.3, if AOB = 125°, then COD is equal to CBSE Circles Class 10 Exercise 9.1 Maths NCERT Exemplar In Fig. 9.3, if AOB = 125°, then COD is equal to (A) 62.5° (B) 45° … WebIn the given figure, if ∠AOB=125 ∘, then ∠COD is equal to : A 62.5 ∘ B 45 ∘ C 125 ∘ D 55 ∘ Easy Solution Verified by Toppr Correct option is D) Opposite sides of a quadrilateral …
WebIn the figure, given below, ABCD is a cyclic quadrilateral in which ∠BAD = 75°; ∠ABD = 58° and ∠ADC = 77°. Find: ∠BDC ∠BCD ∠BCA. VIEW SOLUTION Exercise 17 (A) Q 11 Page 258 In the following figure, O is centre of the circle and ΔABC is equilateral. Find: (i) ∠ADB, (ii) ∠AEB. VIEW SOLUTION Exercise 17 (A) Q 12 Page 258
WebIn Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° 3. In Fig. 9.4, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the … high alert medication list 2021high alert medication patient handoutWebIn figure, if ∠AOB=125∘. Then ∠ COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution We know that, the opposite sides of a quadrilateral circumscribing a circle subtend … high alert medication policy for hospitalWebAnswer: Let O be the centre of two concentric circles C 1 and C 2 , whose radii are r 1 = 4 cm and r 2 = 5 cm. Now, we draw a chord AC of circle C 2 which is tangent to circle C 1 at B. Also, join OB, which is perpendicular to AC. So ∆ OBC is a right-angled triangle ∴ (OB) 2 + (BC) 2 = (OC) 2 (Pythagoras theorem) (4) 2 + (BC) 2 = (5) 2 high alert medication labelingWebAug 24, 2024 · In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° - Sarthaks eConnect Largest Online Education Community. how far is glen falls from lake georgeWebAug 28, 2024 · Best answer (D) 55° ABCD is a quadrilateral circumscribing the circle We know that, the opposite sides of a quadrilateral circumscribing a circle subtend … how far is glenolden pa from trenton njWebIn figure, if ∠AOB = 125°, then ∠COD is equal to 55°. Explanation: As in the given figure ABCD is a quadrilateral circumscribing the circle and we know that, the opposite sides of a … high alert medication policy pdf