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In fig. 6.2 bac 90° and ad  bc. then

WebWe observe that ADB is a right angle triangle with D equal to 90 degrees. By Pythagorean theorem, AD² + BD² = AB² (h)² + (x/2)² = (x)². h² + x²/4 = x². h² = x² - x²/4. h² = [(4-1)/4]x². h² … WebIn Fig. 6.13, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is (a) 50° (b) 40° (c) 70° (d) 60° 25. If one angle of a triangle is equal to the sum of the other two angles, the triangle is (a) obtuse (b) acute (c) right (d) equilateral 26.

In the given figure, ∠BAC = 90^0 and AD⊥BC. Then,

WebOct 19, 2024 · Then Undefined control sequence \operatorname is equal to (а) 5 (b) 25 (c) (d) Answer 10. In ∠BAC = 90° and AD ⊥ BC. A Then (а) BD.CD = BC² (б) AB.AC = BC² (c) BD.CD = AD² (d) AB.AC = AD² Answer 11. D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE BC. WebJun 29, 2024 · In the given figure, ∠BAC = 90° and AD⊥BC. Then, (a) BC.CD = BC2 (b) AB.AC = BC2 (c) BD.CD = AD2 (d) AB.AC = AD2 triangles class-10 1 Answer +1 vote answered … liberty-eylau isd tx https://redcodeagency.com

In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, - Sarthaks

WebJun 28, 2024 · In the figure, if ∠BAC = 90° and AD ⊥ BC. Then, (A) BD . CD = BC 2 (B) AB . AC = BC 2 (C) BD . CD = AD 2 (D) AB . AC = AD 2 Solution: (C) In ∆ABC, ∠B + ∠BAC + ∠C = … WebMar 22, 2024 · Ex 6.2, 1 In figure (i) ,DE BC. Find EC in (i) It is given that DE II BC Hence , / = / Putting the values 1.5/3 = 1/ 1.5 EC = 1 3 EC = (1 3)/1.5 EC = 2 cm Ex 6.2, 1 In figure (ii), … WebAug 18, 2024 · In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, (A) BD . CD = BC 2 (B) AB . AC = BC 2 (C) BD . CD = AD 2 (D) AB . AC = AD 2 triangles ncert class-10 Please log in or … liberty eylau middle school map

In Fig. 6.2, ∠BAC = 90° and AD BC. Then, - Cuemath

Category:In Fig. 6.2, ∠BAC = 90° and AD BC. Then, - Cuemath

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In fig. 6.2 bac 90° and ad  bc. then

In the figure given below , BAC = 90^0 and AD BC. then …

WebExample 5 : Observe Fig. 6.30 and then find P. Fig. 6.30 Solution : In ABC and PQR, Rationalised 2024-24 92 MATHEMATICS. AB 3.8 1 , BC 6 1 CA 3 3 1 and RQ 7.6 2 QP 12 2 PR 6 3 2. AB BC CA That is, RQ QP PR WebMar 29, 2024 · Ex 6.2, 4 In figure, DE AC and DF AE. Prove that, prove that 𝐵𝐹/𝐹𝐸 = 𝐵𝐸/𝐸𝐶 Given: DE II AC and DF II AE To prove: 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Proof: From (1) and (2) 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Hence proved Next: Ex 6.2, 5 Important → Ask a doubt Chapter 6 Class 10 Triangles Serial order wise Ex 6.2

In fig. 6.2 bac 90° and ad  bc. then

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WebJun 3, 2024 · In Fig. 6.13, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is (a) 50° (b) 40° (c) 70° (d) 60° asked Aug 16, 2024 in Mathematics by AbhinavMehra ( 22.6k points) triangles WebAug 5, 2024 · AB 2 + BC 2 = (6\(\sqrt{3}\)) 2 + (6) 2 = 108 + 36 = 144 = (12) 2 AB 2 + BC 2 = AC 2 ∴ ∠B = 90° … [Above theorem. Question 43. In the given figure, BL and CM are …

WebNov 18, 2024 · In fig 6.2 angle BAC =90° and AD perpendicular to BC Get the answers you need, now! kshitijmishra935 kshitijmishra935 19.11.2024 Math Secondary School answered In fig 6.2 angle BAC =90° and AD perpendicular to BC 1 See answer Advertisement Advertisement dualruksha dualruksha Answer: I hope this is correct answer.

WebSolution Verified by Toppr Given:- Let ABCD be the quadrilateral circumscribing the circle with centre O. The quadrilateral touches the circle at point P,Q,R and S. To prove:- … WebHere, the corresponding two sides and the perimeters of two triangles are proportional, then third side of both triangles will also in proportion. Question 8: If in two right triangles, one of the acute angles of one triangle is equal to an acute angle of the other triangle. Can you say that two triangles will be similar? Why? Solution: True

WebMar 7, 2024 · In the given figure, angle BAC = 90° and AD perpendicular BC. Then, A)BC.CD = BC² B)AB.AC =BC² C) BD.CD = AD² D)AB.AC = AD² Answer: Option C) BD.CD = AD² …

WebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to the question, we have, ∠D = ∠D = 90° (∵ AD ⊥ BC) ∠DBA = ∠DAC [each angle = 90°- ∠C] Using AAA similarity criteria, ∆ADB ∼ ∆ADC BD/AD = AD/CD BD.CD = AD 2 2. mcgraw hill math grade 8WebIn Fig. 6.2, ∠BAC = 90° and AD BC. Then, a. BD . CD = BC 2 b. AB . AC = BC 2 c. BD . CD = AD 2 d. AB . AC = AD 2. Solution: Given, ∠BAC = 90° Also, AD BC. We know that a perpendicular drawn from the vertex of the right angle of a right triangle to its hypotenuse divides the triangle into two triangles which are similar to the whole ... mcgraw hill math grade 8 answer keyWebMay 18, 2024 · In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in the figure is (A) 1 (B) 2 (C) 3 (D) 4 geometry class-6 1 Answer +1 vote answered May 18, 2024 by Varun01 (53.6k points) selected May 22, 2024 by Subnam01 (C) 3 We have, ∠BAC = 90° and AD ⊥ BC ∵ ∠BDA = ∠CDA = ∠BAC = 90° ∴ There are 3 right triangles formed in the given … liberty f4920sdWebABC is an isosceles triangle with AB =AC and D is a point on BC such that AD⊥BC(Fig. 7.13). To prove that ∠BAD=∠CAD,a student proceeded as follows: ΔABDand ΔACD, AB =AC (Given) ∠B=∠C (because AB =AC) and ∠ADB=∠ADC Therefore, ΔABD≅ΔACD(AAS) So, ∠BAD=∠CAD(CPCT) What is the defect in the above arguments? View Answer liberty-eylau school districtWebIn the given figure, ∠BAC = 90 0 and AD⊥BC. Then, (a) BC.CD = BC 2 (b) AB.AC = BC 2 (c) BD.CD = AD 2 (d) AB.AC = AD 2 triangles class-10 1 Answer 0 votes answered Sep 4, 2024 by AmirMustafa (60.4k points) selected Sep 16, 2024 by Vikash Kumar Best answer (c) BD.CD = AD2 In ∆ BDA and ∆ADC, we have: liberty eylau isd texarkana txWebIn the given figure, `angle BAC=90^(@) and AD bot BC`.then, liberty eylau water companyWebMar 29, 2024 · Transcript. Question 3 In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, BD . CD = BC2 (B) AB . AC = BC2 (C) BD . CD = AD2 (D) AB . AC = AD2 From Theorem 6.7, If a … Transcript. Question 4 The lengths of the diagonals of a rhombus are 16 cm and … liberty eylau school calendar