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If sina 4 3 then seca is equal t

WebIf in a ΔABC , ∠B = π/3, then the maximum value of sinA sinC is If tanA, tanB, tanC are the solutions of the equation x^3 - k^2x^2 - px + 2k + 1 = 0 Prove that there exist exactly two non-similar isosceles triangles ABC such that tanA + tanB + tanC… Web30 mrt. 2024 · If tan⁡A=3/4 , find the value of 1/sin⁡A +1/cos⁡A Get live Maths 1-on-1 Classs - Class 6 to 12. Book 30 minute class for ₹ 499 ₹ 299. Transcript. Show More. Next: Question 25 (Choice - 2) → Ask a doubt . Class 10; Solutions of …

Sin A) (Sec A - Cos A) = 1 / Tan A + Cot A. - NextGurukul

Web5 aug. 2013 · If SinA+sin^2A=1then cos^2A+cos^4A=1; Trigonometry; The angle of elevation of a cloud from a point h meter above a lake is beeta and the angle of depression of its reflection in the lake is alpha .prove that the height of the cloud above the lake is h (tan alpha+tan beeta )/(tan alpha _tan beeta) meter. cot/1+tan=tan-1/2-sec; Please solve this!! WebIf sin A = 3 4 , calculate sec A? Solution Computing the required values: Given: sin A = 3 4 → 1 We know, by sin definition; sin A = P H = 3 4 → 2 By comparing equation 1 and 2, we have Perpendicular P = 3, and Hypotenuse H = 4 On using Pythagoras theorem in A B … scott county missouri assessor office https://redcodeagency.com

4tanA=3 then find tha value of 4sinA-cosA/4sinA+cosA - Brainly

WebQ: If 4 sinA + secA = 0 then tanA equals to (A) 4 + √2 (B) – 2 + √3 (C) 2 + 4√3 (D) –2 –√3. Sol. 4sinA + secA = 0 $\large 4 sinA + \frac{1}{cosA} = 0 $ $\large \frac{4sinA cosA + … WebAnswer (1 of 3): Given: sinA - cosA = (√3–1) /2 (SinA - cos A)^2 + (sinA + cosA)^2= 2 => (sinA + cosA)^2 = 2 - {(√3 - 1)/2}^2 => (sinA + cosA)^2 = 2-{(4–2√3 ... Web20 dec. 2016 · There’s a very cool second proof of these formulas, using Sawyer’s marvelous idea.Also, there’s an easy way to find functions of higher multiples: 3A, 4A, and so on. Tangent of a Double Angle. To get the formula for tan 2A, you can either start with equation 50 and put B = A to get tan(A + A), or use equation 59 for sin 2A / cos 2A and … scott county missouri assessor

If 4 sinA + secA = 0 then tanA equals to – Quantum Study

Category:If tan A = 5/12, find the value of (sin A + cos A) sec A.

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If sina 4 3 then seca is equal t

If 4 sinA + secA = 0 then tanA equals to – Quantum Study

Web1 feb. 2024 · The most used trigonometric angles for computations include 0°, 30°, 45°, 60°, and 90° . Given: 4tanA=3. To find: Solution: As it is given. 4 tan A = 3, therefore, We know that. So here perpendicular = 3k and base = 4k. First, we need to find out the hypotenuse using the Pythagoras theorem, WebIf sin α = \(\frac{3}{4}\), then cos α is - Q8. If the length of a shadow cast by a pole is √3 times the length of the pole, then the angle of elevation of the sun is -

If sina 4 3 then seca is equal t

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Web2 apr. 2024 · Prove that 1−sinA1+sinA =secA+tanA Prove that 1+sinAcosA +cosA1+sinA =2secA ... + k = 0 has equal roots, find the value of k. Topic: Quadratic Equations . Book: Mathematics Class 10 (RD Sharma) View 3 solutions. View more. ... polynomial are 2 and 3 1 respectively then the (3) c = ... WebClick here👆to get an answer to your question ️ Show that √(1 + sin A/1 - sinA) = secA + tanA. ... Storms and Cyclones Struggles for Equality The Triangle and Its Properties. …

Web24 jun. 2024 · Solution: We have 4tanA = 3 so, tanA = 3/4 . Now, (4sinA - cosA)/(4sinA + cosA) First of all divide by cosA on both LHS and RHS , (4sinA/cosA - … Web2 sep. 2014 · If SinA+sin^2A=1then cos^2A+cos^4A=1; Trigonometry; The angle of elevation of a cloud from a point h meter above a lake is beeta and the angle of depression of its reflection in the lake is alpha .prove that the height of the cloud above the lake is h (tan alpha+tan beeta )/(tan alpha _tan beeta) meter. cot/1+tan=tan-1/2-sec; Please solve this!!

WebSin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse /base SecA=4/√7 0Thank You It'S Krishna 2 years ago Diya soni you copied my answer 0Thank You Divya Soni 2 years ago WebWelcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get …

Web6 sep. 2024 · Math Secondary School answered If seca-coseca=4/3,then what is (sina-cosa) equal to? See answer Advertisement ArtOfSmart As we know that Sin theta + Cos …

Web28 mrt. 2024 · Ex 8.1, 3 - Chapter 8 Class 10 Introduction to Trignometry (Term 1) Last updated at March 28, 2024 by Teachoo. This video is only available for Teachoo black … scott county missouri circuit clerkWeb29 mrt. 2024 · Question 3 If sin⁡𝜃 = x and sin⁡𝜃 = y , then tan⁡𝜃 is (a) 𝑥𝑦 (b) 𝑥/𝑦 (c) 𝑦/𝑥 (d) ... Question 3 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Basic [MCQ] - Solutions of Sample Papers for Class 10 Boards. Last … scott county missouri circuit clerk officeWeb29 mrt. 2024 · Question 3 If sin⁡𝜃 = x and sin⁡𝜃 = y , then tan⁡𝜃 is (a) 𝑥𝑦 (b) 𝑥/𝑦 (c) 𝑦/𝑥 (d) ... Question 3 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Basic [MCQ] - … pre packaged iced coffeeWebSin A = 3/4 =perpendicular /base P=3 H=4 We can find tha base by pythagoras theorem in triangle ABC BA²=AC²-BC² BA²=4²-3² BA²=16-9 BA²=7 BA=√7 SecA = hypotenuse … scott county missouri clerkpre packaged individual cookiesWeb24 nov. 2014 · sinA = 3 5 = O H ⇒ Let {O = 3 H = 5. By Pythagorean Theorem, A = √H2 −O2 = √52 −32 = √16 = 4. Hence, secA = H A = 5 4. I hope that this was helpful. Answer link. scott county missouri court recordsWeb4 jun. 2024 · Explanation: Since 0 < A < 90o we know that ∠A is in the first quadrant. Consider the right OAB where O is the origin and side AB is opposite ∠A We are told that sinA = 1 3 ∴ side AB = 1 and side OA = 3 Applying Pythagoras (OA)2 = (AB)2 + (OB)2 ∴ 32 = 12 + OB2 OB = √9 −1 [Since OB > 0 because ∠A is in the first quadrant] OB = √8 = 2√2 scott county missouri assessor parcel search