Web24 dec. 2024 · Find an answer to your question a,b,c are in ap (b+c)2-c2,(c+a)2-b2,(a+b)2-c2 are in ap. An employee of a telephone company spends 2/5 of his allowance on food and 1/3 of the remainder on rent.the rest of his allowance is divided equally t … WebSolution: As given : a, b, c are in G.P. ⇒ b2 = ac The given expression : a2−b21 + b21 = a2−ac1 + ac1 [using b2 = ac] = a(a−c)1 + ac1 = ac(a−c)c+a−c = ac(a−c)a = ac−c21 = b2−c21 [using ac = b2 ]
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Web10 apr. 2024 · Calculation: Given: b 2, a 2, c 2 are in AP. As we know, If a constant quantity is added to each term of an AP then the resulting terms are also in AP. By adding ab + … WebCorrect option is C) x=1+a+a 2+.....∞= 1−a1 y=1+b+b 2+.....∞= 1−b1 and z=1+c+c 2+.....∞= 1−c1 Since, a,b and c are in AP. ⇒1−a,1−band1−c are also in AP. ⇒ 1−a1, 1−b1 and 1−c1 are in HP. ∴ x, y and z are in HP. Video Explanation Was this …
Web24 dec. 2024 · A2 (b+c), b2 (c+a), c2 (a+b) are in A.P., then either a,b,c are inA.P. or rn1. ab+bc+ca=0 2. a+b+c=0rn3. a-b-c=0 4. a-b+c=0. A2 (b+c), b2 (c+a), c2 (a+b) are in … WebIIT JEE 2002: Let a, b, c be in an AP and a2,b2,c2 be in GP, if a < b < c and a+b+c= (3/2), then the value of a is (A) (1/2 √2) (B) (1/2 √3) (C) (Tardigrade - CET NEET JEE Exam App. Exams; Login; Signup; Tardigrade; Signup; Login; Institution; Exams; Blog; Questions; Tardigrade; Question;
WebIf a 2 , b 2 , c 2 are in A.P., prove that a b + c, b c + a, c a + b are in A.P. Advertisement Remove all ads Solution are in A . P a 2, b 2, c 2 are in A . P . ∴ 2 b 2 = a 2 + c 2 ⇒ b 2 − a 2 = c 2 − b 2 ⇒ ( b + a) ( b − a) = ( c − b) ( c + b) ⇒ b − a c + b = c − b b + a WebIf a,b,c are in A.P., and a 2,b 2,c 2 are in H.P., then- This question has multiple correct options A a=b=c B a 2=b 2= 2c 2 C a,b,c are in G.P. D 2−a,b,c are in G.P. Hard …
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Web15 jul. 2024 · Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and … skyrim stuck on loading screen pcWebSolution The correct option is A a = b = c Explanation for correct option: Progression: Given, a, b, c are in Arithmetic Progression 2 b = a + c ⇒ b - a = c - b ⇒ a - b = b - c Also, a 2, … sweaty betty zero gravity leggingssweaty betty yoga teacher discountWebA Série A1 do Campeonato Paulista de Futebol de 2024, ou Paulistão Sicredi 2024 por motivos de patrocínio, foi a 122ª edição da principal divisão do futebol paulista. [ 2] Foi realizada e organizada pela Federação Paulista de Futebol e disputada por 16 clubes. O campeão da competição foi o Palmeiras, que chegou ao segundo título ... skyrim strongest bandit chiefWeb18 sep. 2024 · If a2 b2 c2 are in ap then prove that a/b+c b/c+a c/a+b are in ap Advertisement Expert-Verified Answer 89 people found it helpful mailtoaditee It is given that a^2 , b^2 and c^2 are in an AP So they have a common difference b^2 - a^2 = c^2-b^2 (b - a) (b + a) = (c - b) (c + b) (b - a) / (b + c) = (c - b) / (b + a) Let; sweaty betty vs lululemonWeb7 feb. 2024 · If a < b < c and a + b + c = 3/2 then the value of a is. ← Prev Question Next Question →. +1 vote. 59.4k views. asked Feb 7, 2024 in Mathematics by Akul (72.6k points) Suppose a, b, c are in AP and a 2, b … skyrim summon phantasmal chestWeb17 dec. 2014 · If a,b,c are in AP and a 2, b 2, c 2 are in HP, then prove either a = b = c or a, b, − c 2 are in GP. Ask Question. Asked 8 years, 3 months ago. Modified 8 years, 3 … skyrim stuck in slow motion