Djnz r1
WebJun 20, 2012 · ORG 0000H START : MOV R1,#10 MOV DPTR,#400H BACK : CLR A MOVC A,@A+DPTR MOV P1,A ACALL DELAY INC DPTR DJNZ R1, BACK SJMP START. ORG 0400H DB 3FH,06H,5BH,4FH,66H,6DH,7DH,07H,7FH,6FH END. plzz let me know whether this code could also work thanks a ton ... WebSep 4, 2012 · The microcontroller needs 24 oscillator period in order to execute "DJNZ R1, DELAY". If R1 has a value of 92H (146 decimal) the amount of time it takes until the R1 goes to zero is 146 X 24 = 3504 microseconds. Then the microcontroller executes "DJNZ r2,delay" that takes another 24 microseconds.
Djnz r1
Did you know?
http://www.ee.ncu.edu.tw/~jztsai/EE3046/lecture/8051%20-%20Conditional%20Jumps%20and%20Time%20Delays.htm WebJan 24, 2024 · LCALL DELAY ;call the Delay subroutine JMP FORLOOP ;after 3s jump back to the for loop DELAY: ;delay of 250 x 250 x 24 instruction cycles = 3000000ums = 3s MOV R3, #1d L3: MOV R2, #1d L2: MOV R1, #1d L1: DJNZ R1, L1 DJNZ R2, L2 DJNZ R3, L3 RET ENDLABEL: END
WebApr 9, 2024 · 单片机:编写十字路口交通灯程序 #includereg52.h#define uchar unsigned char#define uint unsigned int//sbit BI=P3^4; //74Ls49的消隐引脚sbit DXR=P1^0; //东西红... WebApr 10, 2024 · a计数式b双积分式c逐次逼近式d并行式158051单片机内有个16位的定时计数器每个定时计数器都有种工作方式 《单片机原理与应用》模拟试卷 007含答案 《单片机原理与应用》模拟试卷 007 一、填空题:(共30 空,每空1 分) 1.
WebNov 8, 2011 · 单片机里DJNZ代表单片指令。. DJNZ RN,REL 是一条件转移指令,先将工作寄存器Rn中的数减“1”,判断结果是否为“0”,不为“0”程序就跳转到行标为REL的地方执 … WebDec 4, 2024 · 2 instruction states to get to this point) MOV R1,A loop1: MOV R2, #250 loop2: MOV R3, #250 loop3: NOP NOP 7 states to get to this point, and none of the above is in …
WebDescription: DA adjusts the contents of the Accumulator to correspond to a BCD (Binary Coded Decimal) number after two BCD numbers have been added by the ADD or ADDC …
WebC7 1 XCH A,@R1 C8 1 XCH A,R0 C9 1 XCH A,R1 CA 1 XCH A,R2 CB 1 XCH A,R3 CC 1 XCH A,R4 CD 1 XCH A,R5 CE 1 XCH A,R6 CF 1 XCH A,R7 D0 2 POP direct D1 2 ACALL addr11 D2 2 SETB bit D3 1 SETB C D4 1 DA A D5 3 DJNZ direct,offset D6 1 XCHD A,@R0 D7 1 XCHD A,@R1 D8 2 DJNZ R0,offset D9 2 DJNZ R1,offset DA 2 … stampin up gift card holder tutorialWeborg 2000h mov r0, #50h mov r1, #16 mov r2, #0 loop: mov a, @r0 cjne a, #30h, next ;32h 为“0”的 ascii 码 inc r2 next: inc r0 djnz r1, loop here: sjmp here end 1) 源程序中用到了哪些伪指令? org 2) 该程序功能是: 用 r2 统计内部 ram50h 开始的 16 个单元中有多少个字 … persistent cough especially after eatingWeb李广弟版单片机基础答案第一章:一填空题111100EH1001110001100100243. 255 51 4. 输入设备5. 84 6. 630 8 1024 7. 位字节字 bit byte word 8. 1111 1111 001 persistent cough fatigueWebIn this code R1 acts as a counter. The counter value is initialized i.e. 10 HEX is loaded to R1. In each iteration, the instruction DJNZ decrements R1 by one until it becomes zero. This … stampin up gift bag punch boardhttp://polyengineeringtutor.com/8051%20Assembly%20Programming.pdf persistent cough causing vomitingWebApr 22, 2024 · mov dptr,#1000h mov r1,#100(#64h) clr loop:movx @dptr,a inc dptr djnz r1,loop sjmp 143.在两个8051 间用模式 进行串行通信,a机并行采集外部开关的输入,然后串行传 输给b机;b机接收后并行输出控制led发光。画出连接示意图,写出完整的程序。 stampin up gift card holder cardsWebDescription: DJNZ decrements the value of register by 1. If the initial value of register is 0, decrementing the value will cause it to reset to 255 (0xFF Hex). If the new value of register is not 0 the program will branch to the address indicated by relative addr.If the new value of register is 0 program flow continues with the instruction following the DJNZ instruction. stampin up gently falling card ideas